18 PTS! From the equation below, identify the slope and a point on the line. y−3=−2(x+1)

ANSWER:  The slope of the given equation is -2 and a point on the given line is (-1, 3)SOLUTION:Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)We need to find the slope of the given equation and a point through which the given line passes.Given equation is in the form of point slope form  .i.e [tex]\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)[/tex] --- eqn 2where,"m" is the slope of the line [tex]\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)[/tex] is point on that line.Now, by comparing (1) and (2)m = -2[tex]x_{1}=-1[/tex][tex]y_{1}=3[/tex]so, the slope of the given equation is -2  and a point on the given line is (-1, 3)